Need a Conveyor Gearmotor Recommendation?
Send the application data below and SMK can help compare a suitable motor, gearbox size, ratio and mounting arrangement.
- Conveyor speed
- Load & inclination
- Pulley diameter
- Duty & starts/hour
- Voltage & quantity
A conveyor gearmotor combines an electric motor and speed reducer into one drive package. Its job is to deliver the output speed and torque required at the conveyor drive shaft. Correct selection improves starting reliability, operating temperature and service life; incorrect selection can cause slow acceleration, nuisance trips, overheating or premature gearbox wear.
1. Collect conveyor data before choosing a motor
The gearmotor cannot be selected reliably from conveyor length or motor kW alone. Start with the driven machine and record the actual operating conditions.
| Input | What to provide | Why it matters |
|---|---|---|
| Conveyor type | Belt, roller, chain, screw or bucket | Indicates friction and load behavior |
| Material load | Maximum kg, distribution and possible accumulation | Defines running and peak torque |
| Speed | Belt speed in m/s or drive shaft rpm | Determines output speed and ratio |
| Geometry | Drive pulley diameter and conveyor inclination | Links linear speed, force and torque |
| Duty | Hours/day, starts/hour and reversible operation | Affects heating and service factor |
| Installation | Mounting, shaft, voltage, frequency and environment | Ensures mechanical and electrical compatibility |
2. Calculate conveyor output speed and gearbox ratio
If conveyor linear speed and drive pulley diameter are known, estimate pulley speed using:
n = pulley rpm, v = belt speed in m/s, D = pulley diameter in m
Next calculate the theoretical gearbox ratio:
For example, a 1450 rpm motor and a required conveyor shaft speed of 29 rpm give a theoretical ratio of 50:1. Select the nearest available ratio and recalculate the actual belt speed using the reducer's published output rpm. Use the motor's rated full-load speed rather than synchronous speed.
3. Calculate output torque and motor power
Torque is the turning force at the drive shaft. If the required conveyor pull F and drive pulley radius r are known:
T = torque in Nm, F = tangential force in N, r = pulley radius in m
Mechanical power can be calculated from shaft torque and speed:
P = power in kW, T = torque in Nm, n = speed in rpm
For a preliminary check from selected motor power:
This calculated value is not permission to exceed the reducer rating. The final combination must remain within the manufacturer's permitted continuous output torque, peak torque, thermal capacity and shaft-load limits.
4. Check startup torque, duty and service factor
A loaded conveyor may need substantially more torque during acceleration than while running. Product accumulation, sticky material, incline, frequent starts and reversing all increase demand. Confirm the motor starting method—direct-on-line, soft starter or variable-frequency drive—and compare the available starting torque with the load requirement.
Service factor accounts for application severity. Operating hours, switching frequency, shock, load inertia and ambient temperature can affect the required factor. Service-factor definitions and ratings are manufacturer-specific, so do not compare a number from one catalog directly with another without checking its basis.
- Light duty: uniform load, limited daily hours and few starts.
- Moderate duty: longer operation, regular starts or varying load.
- Heavy duty: high inertia, shock, frequent starts, reversing or inclined transport.
5. Select gearbox type, shaft and mounting
A worm gearmotor offers compact right-angle transmission, broad ratios and convenient hollow-shaft mounting. A hypoid gearmotor may be preferred where higher efficiency, compact right-angle geometry and long operating hours are priorities. Final choice depends on ratio, torque, efficiency, space, budget and duty.
Confirm solid or hollow output shaft, shaft diameter, key, torque arm, flange or foot mounting, and installation position. Sprocket, belt and pulley drives can apply overhung load to the output shaft; verify this separately. Also confirm lubrication suitability for the mounting position.
6. Conveyor gearmotor calculation example
Assume a conveyor needs 0.20 m/s belt speed and uses a 200 mm drive pulley. The required pulley speed is:
With a motor rated near 1450 rpm, the theoretical reduction ratio is approximately 1450 ÷ 19.1 = 75.9, so a catalog ratio near 75:1 or 80:1 should be evaluated. If the running shaft torque requirement is 120 Nm, the mechanical output power is approximately 120 × 19.1 ÷ 9550 = 0.24 kW.
That does not mean a 0.25 kW gearmotor is automatically correct. Starting torque, acceleration time, efficiency, daily operation, starts per hour, service factor and reducer rated torque still require verification. A higher motor or gearbox size may be needed after these checks.
7. Conveyor gearmotor quotation checklist
For a faster quotation, provide:
- Conveyor type, length and maximum transported load
- Belt speed or required output rpm
- Drive pulley diameter and conveyor inclination
- Running torque and peak torque if calculated
- Operating hours/day, starts/hour and direction
- Motor voltage, frequency and required control method
- Gearbox mounting position and output shaft or hollow-bore dimensions
- Ambient temperature, dust, moisture or washdown conditions
- Required quantity and target delivery date
Explore SMK gear motors, compare worm gear reducers and hypoid gear reducers, or send your conveyor data for selection support.
Frequently asked questions
How do I select a gearmotor for a conveyor?
Calculate required output speed and running torque, then verify startup torque, service factor, duty, shaft load, mounting, electrical supply and environment.
How do I calculate conveyor gearbox ratio?
Divide the motor's rated speed by the required conveyor shaft speed. Recalculate actual conveyor speed using the nearest available catalog ratio.
Should I choose a conveyor motor by kW alone?
No. Motor kW does not prove that the gearbox has adequate output torque or that the drive can start the loaded conveyor. Check both motor and reducer limits.
Does a conveyor need a VFD and a gearbox?
A gearbox provides mechanical speed reduction and torque multiplication. A VFD controls motor speed and acceleration. Many conveyors use both when adjustable speed and controlled starting are required.
Engineering references
Key formulas and selection principles were checked against primary manufacturer technical guidance.
